11.6 OFSA

OFSA for Conics B (Partial)


This page contains peer generated questions that help you assess your understanding. Remember that questions may not represent the rigor of the questions you may be expected to complete on formal assessments. This page is simply an OFSA - opportunity for self assessment.

Question 1
What is the equation for this graph?:
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A:

B:

C:

D:


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Question 2
What is the equation for this graph?:
eyr7p5axh3.png
A:

B:

C:

D:

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Question 3
The Parametric equation:

is equal to which equation?
x=4csc(t), y= 2cot(t), 0
A:

B:

C:

D:

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Question 4
What type of graph does this equation make:



A: Right half of an ellipse
B: Top half of a hyperbola
C: Bottom half of an ellipse
D: Bottom half of a circle

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Question 5
What is the number in front of the radical for the equation of this graph?

Screen shot 2012-05-31 at 10.03.30 PM.png
A: 1
B: 1/3
C: 5/4
D: 1/2

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Question 6
Which direction does the graph of this equation open up, and what portion of the graph is used?



A: Opens North-South, and uses right portion
B: Opens East-West, and uses left portion
C: Opens North-South, and uses bottom portion
D: Opens East-West, and uses top portion

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Question 7
What type of conic created by the following equation?



A.) The top half of a parabola
B.) The bottom half of a parabola
C.) The left half of a parabola
D.) The right half of a parabola

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Question 8
Which of the following is the equation of an ellipse?

A.)

B.)

C.)

D.)


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Question 9
How does vertical shifting of a hyperbola get affected in the following equation?



A.) a
B.) b
C.) c
D.) d

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Question 10
What type of graph does this equation make?
y=3sqrt(4+x^2)

A.) Bottom half of ellipse
B.) Right half of ellipse
C.) Top half of Hyperbola
D.) Right half of Hyperbola
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Question 11
What is the slope of the asymptotes in the graph from problem 10, If they exist?
A.) 2/9
B.) 9/2
C.) 9
D.) do not exist
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Question 12
Find the equation of a semi-ellipse with an eccentricity of 9/25 and the focus at (9,0) (Only right side)
A.) 42
B.) x=sqrt((-25/16)*y)
C.) y=sqrt((-25/16)*x)
D.) (x^2)/25 + (y^2)/16 = 1
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Question 13
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Question 14
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Question 15
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Question 16
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Question 17
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Question 18
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Question 19
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Question 20
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Question 22
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Question 23
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Question 24
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